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Q.

The circuit shown in the figure contains two diodes each with a forward resistance of  50Ω and with infinite reverse resistance. If the battery voltage is 6V, the current through the  100Ω resistance is x100A. The value of x is

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answer is 2.

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Detailed Solution

Diode D1 is forward biased and offers a resistance  50Ω.
Diode D2  is reserve biased and its corresponding resistance is infinite, no current flows through it. As all the resistance are in series, the current through them,
 

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I=V(R1+R2+R3)=6(50+150+100)=0.02A

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