The circuit shown in the figure continues to infinity. The potential difference between points 1 and 2 is $\frac{V}{2}$ , that between points 3 and 4 is $\frac{V}{4}$ and so on; ie., the potential difference becomes 1/2 after every step of the ladder. Find the ratio C₁/ C₂

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

pd across C₁ is $\frac{V}{2}$ so charge on C₁

$\Rightarrow q_{0} = \frac{C_{1} V}{2}$

But total charge supplied by battery is Q₀ = C_eq V.

Hence C₁ = 2C_eq

$C_{eq} = \frac{(C_{eq} + C_{2}) C_{1}}{C_{eq} + C_{2} + C_{1}} \Rightarrow \frac{C_{1}}{C_{2}} = 2$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE