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Q.

The circular head of a screw gauge is divided into 200 divisions and move 1mm ahead in one revolution. If the same instrument has a zero error of -0.05mm and the reading on the main scale in measuring diameter of a wire is 6mm and that on circular scale is 45 . The diameter of the wire is

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a

6.275mm

b

5.50mm

c

5.75mm

d

6.375mm

answer is A.

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Detailed Solution

$\begin{array}{l} L . C = \frac{Pitch}{Number of divisions on circular scale} = \frac{1 mm}{200} = 0.005 mm = 0.0005 cm \\ Diameter of the wire = (Main scale reading + Circular scale reading \times L.C.) - zero error \\ = 6 mm + 45 \times 0.005 - (- 0.05) \\ = 6 mm + 0.225 mm + 0.05 mm = 6.275 mm \end{array}$

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