The circular head of a screw guage is divided into 200 divisions and move 1 mm ahead in one revolution. If the same instrument has a zero error of -0.05 mm and the reading on the main scale in measuring diameter of a wire is 6 mm and that on circular scale is 45. The diameter of the wire is _______ mm.

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6.220 mm

6.225 mm

6.375 mm

6.275 mm

answer is A.

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Detailed Solution

Pitch of screw $= 1 mm$
$L . C = \frac{pitch of screw}{No. of div on circular scale} = \frac{1}{200} = 0 .005 mm$
Diameter = P.S.R + H.S.RXL.C + Error = 6 + 45 x 0.005 + 0.05 = 6 + 0.225 + 0.05 = 6.275mm

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