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The circumcentre of a triangle formed by the line $xy + 2 x + 2 y + 4 = 0$ and $x + y + 2 = 0,$ is

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(-1, -1)

(0, -1)

(1, 1)

(-1, 0)

answer is A.

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Detailed Solution

$x y + 2 x + 2 y + 4 = 0 \Rightarrow (x + 2) (y + 2) = 0$

$O (0, 0), B (0, - 2), C (- 2, 0)$

$B O C = 90^{0}, S = \frac{B + C}{2} = [- 1, - 1]$

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