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Q.

The circumference of a circular playground is 528 m. The total expenditure of repairs of the ground at the rate of Rs.1.50 per square meter will be Rs. ____.


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Detailed Solution

The expenditure to repair the ground will be Rs. 33264.
Concept- Given in the question statement is the circumference of a circle. We have to know the formula to calculate the circumference of a circle which is,
Circumference = https://lh4.googleusercontent.com/ffVKC_Rur4q84kn7_3tl6J7iHc9gSm5IwSqEExRIm15TtcO3Ufm4JQKW2TH7iyt138tyv-mXr_Oi4Z_H04-y9qTE4Wi9SeUYRri0HrZT1mWRhcR-p8vZPOI4p1hSWW-IUis2yzNfRrw5IVCiiQWhere, R = Radius of the circle.
Using the above-mentioned formula of the circumference of a circle as an equation, we will find out the value of R and then, use it in the formula of “Area of a circle”, which goes as follows:
https://lh4.googleusercontent.com/ScEkuVJ0L6fV_X_Xk6zI0_1znFPhECEmb8YkKZ84aT25tEUYcOkVEIH9dw74r390rO_du_86xvRNesTJYwG2EJ1424D3iRWV1wI8RrPQI_mCkt8qV2FSK6oEkDBO-ccnMgQwMCvjMoL_K4YgYgFinally, we will have to multiply the calculated area of the playground with the cost of repair per unit, to obtain the total expenditure of repairs. Given, circumference of a circular playground is 528 m.
Let's assume that "R" is the circle's radius.
528=(2×π×R)  
R= 528 (2×π)  
R= 528 2× 22 7     π= 22 7  
R= 528×7 2×22  
R=84m  
Therefore, Question Image                                  = 22 7 × 84 2       π= 22 7  
                                  = 22 7 ×84×84  
                                   Question ImageSince, the cost of repairs per unit sq. m. is Rs.1.50, total cost of repairing the full playground https://lh4.googleusercontent.com/seMeMaREDuwwIlZwxerFDODs4Px5JTd2icEgMQVuqn3n2T__Cv4xB0AHDFHbJWZCBfkHf6wsu4T4AVKE6MLXo_fzcUQiU3LOwbx9oBkThivW5L4PLGiv2r8bdB-ICbyxGQxlDj4xyBlZsRxviQHence, the correct answer is Rs.33264.
 
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