The circumference of the edge of a hemispherical bowl is 132 cm. When $π$ is taken as $\frac{22}{7}$ , the capacity of the bowl in ${cm}^{3}$ is

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Detailed Solution

$= 132 cm$ Circumference of bowl
$2 πr = 132 \Rightarrow r = 132 \times \frac{7}{22} \times \frac{1}{2} = 21 r = 21 cm, capacity of the bowl = \frac{2}{3} {πr}^{3} = \frac{2}{3} \times \frac{22}{7} \times 21 \times 21 \times 21 = 19404 {cm}^{3}$

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