The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?

Let the number of revolutions completed by rear wheel $=n$ 

Number of revolutions completed by front wheel $=n+5$

Distance travelled by rear wheel $=36nft$ ( $\because$ circumference of rear wheel 36ft)

Distance travelled by front wheel $=30\left(n+5\right)ft$ ( $\because$ circumference of front wheel 30ft)

Distance travelled by both the wheels is same

$\therefore 36n=30\left(n+5\right)\Rightarrow 6n=150\Rightarrow n=25$

Distance $=36n=36\times 25=900ft$