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The circumradius of the triangle formed by (3. 7), (3, - 2), (5,7) is

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$\sqrt{85}$

$2 \sqrt{85}$

$\sqrt{85} / 2$

$\sqrt{85 / 2}$

answer is C.

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Detailed Solution

A(3,7),8(3,-2),C(5,7).

Given vertices form a right angled triangle right angle at A.BC is hypotenuse
If R is the circumradius then $2 R = BC = \sqrt{4 + 81} = \sqrt{85} \Rightarrow R = \sqrt{85} / 2$

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