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Q.

The circumradius of the triangle whose sides are 13, 12 and 5 is _____ .


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a

15

b

13 2  

c

15 2  

d

6 

answer is D.

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Detailed Solution

We are given that the sides of a triangle are 13, 12 and 5 cm.
Now, by using the formula, R= abc (a+b+c)(b+c−a)(c+a−b)(a+b−c)  we have
⇒R= 13×12×5 (13+12+5)(12+5−13)(5+13−12)(13+12−5) ⇒R= 780 (30)(4)(6)(20)  
Multiplying the terms, we get
⇒R= 780 600×4×6  
Rewriting the terms, we get
⇒R= 780 6×100×6×4  
⇒R= 780 10×6×2 ⇒R= 780 120 ⇒R=6  
Therefore, the circumradius of a triangle whose sides are 13, 12 and 5 cm, is 6.
 
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The circumradius of the triangle whose sides are 13, 12 and 5 is _____ .