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The closed cylinder shown in figure has a freely moving piston separating chambers 1 and 2 . Chamber 1 contains 25 mg of $N_{2}$ gas and chamber 2 contains 40 mg of helium gas. When equilibrium is established what will be the ratio $L_{1} / L_{2}$ ? What is the ratio of the number of moles of $N_{2}$ to the number of moles of He? (Molecular weights of $N_{2}$ and He are 28 and 4).

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a

0.026,0.125

b

0.089 ,0.089

c

0.056 , 0.098

d

None of these

answer is B.

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Detailed Solution

$n_{1} = \frac{0.025}{28} = 8.93 \times 10^{- 4} a n d n_{2} = \frac{0.04}{4} = 0.01 ∴ \frac{n_{1}}{n_{2}} = 0.089 I n e q u i l i b r i u m p a n d T a r e s a m e . ∴ p V = n R T ∴ V \propto n or L \propto n ∴ \frac{L_{1}}{L_{2}} = \frac{n_{1}}{n_{2}} = 0.089$

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The closed cylinder shown in figure has a freely moving piston separating chambers 1 and 2 . Chamber 1 contains 25 mg of N2 gas and chamber 2 contains 40 mg of helium gas. When equilibrium is established what will be the ratio L1/L2 ? What is the ratio of the number of moles of N2 to the number of moles of He? (Molecular weights of N2and He are 28 and 4).