Q.

The closest distance of approach of an α- particle travelling with a velocity V towards a stationary nucleus is ‘d’. For the closest distance to become d/3 towards a stationary nucleus of double the charge the velocity of projection of the α - particle has to be

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a

3V/2

b

6V

c

V/56

d

6V

answer is B.

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Detailed Solution

12mαVα2=14πε0.qα×qdVα2qdV22=q2q1d1d2 V12V2=6V1

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