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Q.

 The CO in a 20.3 L sample of gas was converted to CO2 by passing the gas over iodine pentoxide heated to 150° C :

I2O5(s)+5CO(g)5CO2(g)+I2(g)

The iodine distilled at this temperature and was collected in an absorber containing 8.25 mL of 0.01101 M Na2S2O3 . The excess hypo was back-titrated with 2.16 mL of 0.00947 MI 2 solution. The milligrams of CO in 1L of the original gas sample was therefore :

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a

0.172 mg

b

0.283 mg

c

0.349 mg

d

0.506 mg

answer is A.

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Detailed Solution

The complete reaction is,

I2O5+5CO5CO2+I2

8.25×0.011012.16×0.00947×21000×12×5×2820.3

=WCO=0.172mg

Thus, the milligrams of CO in 1 L of the original gas sample is 0.172 mg.

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