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Q.

The coefficient of performance of a carnots refrigerator is 9. If the heat extracted from lower temperature is $900 J$ then heat transferred to the source will be

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a

$100 J$

b

$8100 J$

c

$900 J$

d

$1000 J$

answer is B.

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Detailed Solution

$C O P = \frac{Q_{2}}{w} \Rightarrow 9 = \frac{900}{w} \Rightarrow w = 100 J$

$Q_{1} = Q_{2} + w = 900 + 100 = 1000 J$

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