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Q.

The coefficient of friction between the block and the surface in each of the given figure is 0.4 match column I with that of column II.
Column - I
Column - II
A.
Force of friction is zero in P. Figure (i)
B.
Force of friction is $2 . 5N$ in Q. Figure (ii)
C.
Acceleration of the block is zero in R. Figure (iii)
D.
Normal force is not equal to $2g$ in S. Figure (iv)

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a

$A - PQ, B - PQRS, C - PR, D - PSR$

b

$A - PR, B - RS, C - QS, D - PQRS$

c

$A - PQRS, B - PR, C - R, D - PQ$

d

$A - PR, B - QS, C - PQRS, D - RS$

answer is D.

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Detailed Solution

a) Force of friction is zero in P and R because block has no tendency to move

(b) Force of friction is 2.5 N in (Q) and (S) because applied force in horizontal direction in both is $2 . 5N$

(c) a is zero in all cases

(d) Normal force is not equal to 2g in (R) and (S) because some extra vertical force is also acting

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The coefficient of friction between the block and the surface in each of the given figure is 0.4 match column I with that of column II.Column - IColumn - IIA.Force of friction is zero inP.Figure (i)B.Force of friction is 2.5N inQ.Figure (ii)C.Acceleration of the block is zero inR.Figure (iii)D.Normal force is not equal to 2g inS.Figure (iv)