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Q.

The coefficient of friction between the box A and the cart is 0.7. The box is of mass 2 kg. The minimum acceleration of cart so that block does not fall down is

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a

$5 {ms}^{- 2}$

b

$10 {ms}^{- 2}$

c

$14 {ms}^{- 2}$

d

$8 {ms}^{- 2}$

answer is B.

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Detailed Solution

$mg = μ (N)$

$mg = μ ma$

$a = \frac{g}{μ} = \frac{9.8}{0.7}$

$= \frac{98}{7} = 14 m / s^{2}$

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