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Q.

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms-1starting from rest is nearly g=10ms−2

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a

16.4 m

b

18.3 m

c

8 m

d

4.1 m

answer is A.

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Detailed Solution

Given that

μ=0.4,s=?,v=8m/s,u=0,g=10ms−2

v2−u2=2as f=μmg

⇒82−02=2μsgs fm=μg

∴S=8×82×0.4×10 a=μg

∴S=648=8m

∴S=8m

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