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Q.

The coefficient of static friction between the box and the train's floor is 0.2. The maximum acceleration of the train in which a box lying on its floor will remain stationary is

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a

2 m s-2

b

4 m s-2

c

6 m s-2

d

8 m s-2

answer is A.

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Detailed Solution

As acceleration of the box is due to static friction,

ma=fs≤μsN=μsmg a≤μsg ∴amax=μsg           =0.2×10 m s-2           =2 m s-2

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