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The coefficient of static friction, µ_s between block A of mass 2 kg and the table as shown in figure, is 0.2.
What would be the maximum mass value of block B so that the two blocks do not move ? The string and the pulley are assumed to be smooth and massless. (g = 10 m/s²)

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2.0 kg

0.2 kg

4.0 kg

0.4 kg

answer is D.

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Detailed Solution

The different forces acting on the two masses are shown in fig.

ln equilibrium, T = M g …(1)

Further T= µmg …(2)

$\begin{array}{l} ∴ Mg = μmg \\ M = μ m = 0 \cdot 2 \times 2 = 0 \cdot 4 kg \end{array}$

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