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Q.

The coefficient of surface tension of a liquid is 5Nm−1. If a film is held on a ring of area 0.02 m2, its total surface energy is about

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a

2×10−2J

b

2×10−1J

c

3×10−1J

d

2.5×10−2J

answer is C.

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Detailed Solution

Surface energy is related to the surface tension by the relation

U = TdA

Given, T=5Nm−1

dA = 2A

2×0.02=0.04m2∴U=5×0.04=0.20J=2×10−1J

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