The coefficient of $\mathrm{x}$ in the expansion of ${(\mathrm{x}+2)}^3$ is:

The given polynomial is ${(\mathrm{x}+2)}^3$_.

We know the algebraic identity:
${\mathbf{(}\mathbf{a}\mathbf{+}\mathbf{b}\mathbf{)}}^{\mathbf{3}}\mathbf{=}{\mathbf{a}}^{\mathbf{3}}\mathbf{+}{\mathbf{b}}^{\mathbf{3}}\mathbf{+}\mathbf{3}{\mathbf{a}}^{\mathbf{2}}\mathbf{b}\mathbf{+}\mathbf{3}{\mathbf{ab}}^{\mathbf{2}}$

Here, $\mathrm{a}=\mathrm{x}$  and $\mathrm{b}=2.$

Therefore, using the above identity, we have,

${\left(\mathrm{a}+\mathrm{b}\right)}^3={\mathrm{x}}^3+2^3+(3{\mathrm{x}}^2\times 2)+(3\mathrm{x}\times 2^2)$

$={\mathrm{x}}^3+8+6{\mathrm{x}}^2+(3\mathrm{x}\times 4)$

$={\mathrm{x}}^3+6{\mathrm{x}}^2+12\mathrm{x}+8$

The coefficient of $\mathrm{x}$ is 12.

Therefore, the coefficient of $\mathrm{x}$ in the expansion of ${(\mathrm{x}+2)}^3$ is 12.

Hence, 12 is the correct answer.