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Q.

The coefficient of x5 in 1+x21+1+x22+...+1+x30 is

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a

C5   51

b

C5   9

c

C6   31-C6   21

d

C5   30-C5   20

answer is C.

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Detailed Solution

 =(1+x)21+(1+x)22+.....+(1+x)30  =(1+x)21 1+(1+x)+(1+x)2+....(1+x)9  =(1+x)21,  1+x10-1(1+x)-1 =1+x31-(1+x)21x

Coefficient of  x5=Coeff x6 in Nr

               =C6  31-C6  21 

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