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Q.

The coefficient of  xr(0r(n1)) in the expansion of (x+3)n1+(x+3)n2(x+2)+(x+3)n3(x+2)2++(x+2)n1 is 

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a

nCr(3r+2nr)

b

nCr(3r2n)

c

nCr(3nr2nr)

d

nCr(3r2nr)

answer is B.

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Detailed Solution

(x+3)n1+(x+3)n2(x+2)+(x+3)n3(x+2)2++(x+2)n1

we know that

anbn=(ab)(an1+an2b++bn1)

Given expression

(x+3)n(x+2)n(x+3)(x+2)=(x+3)n(x+2)n1

Coefficient of xr in  (x+3)n(x+2)n

nCnr3nrnCnr2nr=nCr(3nr2nr)

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