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Q.

The coefficient of x2012 in the expansion of (1x)20081+x+x22007, is

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a

 2012C2008

b

none of these

c

 2012C2009

d

 2012C2007

answer is D.

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Detailed Solution

We have

(1x)20081+x+x22007=(1x)1x320071x32007x1x32007

We find that x2012 is of the form x3r+2 where as 1x32007

contains terms of the form x3r and x1x32007 contains terms of the form x3r+1 So, there is no term containing x2012 in the given expansion 

Hence, coefficient of x2012 is zero.

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