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Q.

The Coefficient of x5 in th expansion of (x2+2x+3)5 is ______

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answer is 1052.

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Detailed Solution

(x2+2x+3)5  5!p!q!r!x2p2xq3r:p+q+r=5 For coefficient of x5=

pqr
050
131
212

5!5!25+5!3!233+5!2!2!232=32+480+540=1052

The Coefficient of x5 is 1052

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