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Q.

The coefficient of x5 in the expansion of (1+x)21+(1+x)22+(1+x)23 +........... + (1+x)30 is

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a

51C5

b

31C6-21C6

c

31C6+20C5

d

9C5

answer is C.

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Detailed Solution

(1+x)21+(1+x)22++(1+x)30
=(1+x)21(1+x)101(1+x)1=1x(1+x)31(1+x)21
 Coefficient of x5 in the given expression  = Coefficient of x5 in 1x(1+x)31(1+x)21 = Coefficient of x6 in (1+x)31(1+x)21 =31C621C6

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