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Q.

 The coefficient of x9 in the expansion of (1+x)(1+x2)(1+x3)...(1+x100) is.......

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answer is 8.

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Detailed Solution

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In expansion of  (1+x)(1+x2)(1+x3)....(1+x100)

x9 can be found in the following ways 

x9,x1+8,x2+7,x3+6,x4+5,x1+2+6,x1+3+5,x2+3+4

The coefficient of x9 in each of the above 8 cases is 1.

Required coefficient =8

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