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Q.

The coefficient of xn in the polynomial (x+nC0)(x+3.nC1)(x+5nC2)[x+(2n+1)nCn]  is

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a

n.2n+1

b

(n+1)2n

c

n.2n+1

d

n.2n

answer is C.

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Detailed Solution

(x+nC0)(x+3.nC1)(x+5nC2)[x+(2n+1)nCn]

=xn+1+(nC0+3.nC1+5.nC2++(2n+1).nCn)xn+

xncoefficient=[nC0+3.nC1+5.nC2++(2n+1).nCn]

We know that

a.C0+(a+d)C1+(a+nd)Cn=(2a+nd)2n1

here  a=1,d=2

[2(1)+n(2)]2n1

=2(n+1)2n1

=(n+1)2n

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