The columbic force between two $α$ - particles separated by a distance of $8.2 \times 10^{- 5} m$ in air is

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60 N

140 N

14 N

120 N

answer is B.

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Detailed Solution

$q_{1} = q_{2} = 2 \times 1.6 \times 10^{- 19} C$

$\frac{1}{4 π ε_{0}} . \frac{q_{1} q_{2}}{r^{2}} = \frac{9 \times 10^{9} \times 4 \times 2.56 \times 10^{- 38}}{8.2 \times 8.2 \times 10^{- 30}}$ $= 1.37 \times 10^{1} = 13.7 = 14 N$

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