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Q.

The combined equation to a pair of straight lines passing through the origin and inclined at 450, 600 with x-axis is

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a

3x2+3+1xy+y2=0

b

3x23+1xyy2

c

3x23+1xy+y2=0

d

3x231xy+y2

answer is C.

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Detailed Solution

Letθ1=450m1=Tanθ1=Tan450=1θ2=600m2=Tanθ2=Tan600=3  Equation  of  lines  are  y=m1x,  y=m2x

y=x,             y=3xxy=0,       3xy=0  combained  Equation  is  xy3xy=03x23+1xy+y2=0

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