The combustion of 2·propanol $(M = 60.0 g \times {mol}^{- 1})$
occurs according to the equation,
$\begin{aligned} 2 {CH}_{3} {CHOHCH}_{3} (l) + 9 O_{2} (g) ⟶ 6 {CO}_{2} (g) + 8 H_{2} O (l) \end{aligned}$
What is q for the combustion of 15.0 g of 2-propanol
${CH}_{2} {CHOHCH}_{3} (l)$ ${CO}_{2} (g)$ $I_{2} O (t)$
$Δ H_{f} kJ \cdot {mol}^{- 1}$ $- 318.2$ $- 393.5$ $- 285.8$

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$- 5.01 \times 10^{2} kJ$

$- 1.00 \times 10^{3} kJ$

$- 2.01 \times 10^{3} k_{J}$

$- 4.01 \times 10^{3} kJ$

answer is A.

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Detailed Solution

Value of q for the combustion,

$\begin{array}{l} q = [- 393.5 \times 6 - 285.8 \times 8 + 318.2 \times 2] \times \frac{1}{2} \times \frac{15}{60} \\ = - 5.01 \times 10^{2} kJ \end{array}$

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