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The combustion of one mole of liquid benzene takes place at 290K and 1 atm. After combustion, $C O_{2} (g)$ and $H_{2} O (l)$ are produced and 3267.0 Kj of heat produced. Standard enthalpy of formation of $C O_{2} (g)$ and $H_{2} O (l)$ are -393.5 kj/mol and -285.8 kj/mol respectively. The standard enthalpy of formation of liquid benzene in kj/mol is

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answer is 48.6.

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Detailed Solution

NCERT P.No: 170

$C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \overset{}{\to} 6 C O_{2} (g) + 3 H_{2} O (l) - 3267 = (6 \times - 393.5 + 3 \times - 285.8) - (Δ_{f} H^{0} C_{6} H_{6} (l) + 7.5 \times 0) ∴ Δ {H^{0}}_{f} C_{6} H_{6} (l) = + 48.6 k g / m o l$

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