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Q.

The common factor of $z^{2}$ $(x^{2} y - x y^{2})$ and $8 (x^{4} y^{2} - x^{2} y^{4})$ is

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a

x^{2} y^{2}

b

x y (x - y)

c

2 x y

answer is C.

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Detailed Solution

z^{2} (x^{2} y - x y^{2}) = z \times x \times y (x - y)

$8 (x^{4} y^{2} - x^{2} y^{4}) = 2 \times x^{2} \times y^{2} \times (x + y) (x - y)$

Among them common is $x y (x - y)$

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