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Q.

The complex ion [Fe (CN)6]4- contains :

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a

Total of 36 electrons on Fe2+ cation.

b

sp3d2 hybrid  orbitals with octahedral structure 

c

Total of 104 electrons

d

Six sigma bonds

answer is A.

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Detailed Solution

EAN=Z−X+Y
Z=Atomic number of the metal
X=Number of electrons lost during the formation of the metal ion from its atom
Y=Number of electrons donated by the ligands
For [Fe(CN)6​]4−
EAN=Z−X+Y=26−2+12=36.
Thus total of 36 electrons are present on Fe2+ cation.
Thus option 1 is correct.
The complex [Fe(CN)6​]4− involves d2​sp3​ hybridization and has octahedral geometry.
Thus option 2 is incorrect.
Total number of electrons in [Fe(CN)6​]4− is 36+6(12)=108. Thus, option 3 is incorrect.
The complex contains 12 sigma bonds. Six are between Fe and C and six are present in six CN ligands. Thus, option 4 is incorrect.

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