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Q.

The complex numbers z=x+iy which satisfy the equation 

z5iz+5i=1 lie on 

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a

none of these 

b

circle through the origin 

c

the  x-äxis 

d

straight line y=5

answer is A.

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Detailed Solution

detailed_solution_thumbnail

|z5i|=|z+5i|

The distance of z from 5i

 and 5i are equal. 

The distance of (x,y) from (0,5)

and (0, - 5) are equal. 

Question Image

 (x,y) lies on the perpendicular bisector of the line segment joining (0, - 5) and (0, 5) which is the

x-axis. 

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The complex numbers z=x+iy which satisfy the equation z−5iz+5i=1 lie on