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Q.

The complex with highest number of unpaired electrons is 

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a

K4[FeF6]

b

[Ti(H2O)6]3+

c

 [Cr(NH3)6]3+

d

K4[Fe(CN)6]

answer is B.

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Detailed Solution

  • In complex K4[Fe(CN)6], iron has 0 unpaired electrons because, cyanide is a strong field ligand. 
  • In complex K4[FeF6], iron has 4 unpaired electrons. 
  • In complex [Ti(H2O)6]3+, titanium has 1 unpaired electron. 
  • In complex [Cr(NH3)6]3+, chromium has 3 unpaired electrons. 
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