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The composition of a sample of formula $N i 0.98 O 1.00$ percentage Ni present in the form of $Ni (III) is:$

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answer is B.

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Detailed Solution

2 x + 3 (98 − x) = 200 x = 94

% N i 2 + = 9498 × 100 = 96

%Ni + 3 = 98 − 94 98 × 100 = 4 %

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