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The composition of residual mixture will be if 30 g of Mg combines with 30 g of oxygen

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$40 g Mg + 20 g O_{2}$

$45 g MgO + 15 g O_{2}$

$50 g MgO + 10 g O_{2}$

$60 g MgO only$

answer is C.

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Detailed Solution

$Mg + \frac{1}{2} O_{2} \to MgO$

24 gram Mg = 16 gram $O_{2} = 40 grams MgO$

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