The composition of yellow precipitate when a solution of ammonium molybdate is added to hot solution of arsenic salt is

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$\begin{aligned} {({NH}_{4})}_{3} {AsO}_{4} \cdot 6 {MoO}_{2} \end{aligned}$

${({NH}_{4})}_{3} {AsO}_{4} \cdot 12 {MoO}_{2}$

${({NH}_{4})}_{3} {AsO}_{4} \cdot {MoO}_{2}$

${({NH}_{4})}_{3} {AsO}_{4} \cdot 4 {MoO}_{2}$

answer is A.

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Detailed Solution

The composition of yellow precipitate when a solution of ammonium molybdate is added to hot solution of arsenic salt is ${({NH}_{4})}_{3} {AsO}_{4} \cdot 12 {MoO}_{2}$

The yellow precipitate that forms when ammonium molybdate solution is added helps identify phosphotes. Yellow compound known as ammonium phosphomolybdate

Hence option A is correct

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