The compound A decomposed ( $A \to products$ ) by first order kinetics. If the concentration of A dropped from 0.1 M to 0.05 M in 30 minutes, find the rate of reaction after 60 minutes, from start in $M \min^{- 1}$ :

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$\frac{\ln 2}{600}$

$\frac{\ln 2}{120}$

$\frac{\ln 2}{60}$

$\frac{\ln 2}{1200}$

answer is A.

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Detailed Solution

Rate of reaction after 60 minutes, from start in $M \min^{- 1}$

$\begin{array}{l} t_{1 / 2} = 30 \min \\ [A]_{t} = 0.025 \\ r = \frac{0.693}{30} \times 0.025 \\ = \frac{\ln 2}{1200} \end{array}$

Hence, the correct option is a.

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