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The compound interest when principal is Rs. $10, 000$ , Rate $= 12 % p . a$ number of year $= 2$ is

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3544

2544

12544

2454

answer is A.

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Detailed Solution

$P = 10, 000$

$R = 12 % p . a$

$n = 2$

$A = P {(1 + \frac{R}{100})}^{n}$

$= 10, 000 {(1 + \frac{12}{100})}^{2}$

$= 10, 000 \times \frac{112}{100} \times \frac{112}{100}$

$= 112 \times 112 = 12544$

$C . I = A - P$

$= 12544 - 10, 000$

$=$ Rs.2544

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