The compound interest when principal is Rs.$10,000$, Rate $=12\%p.a$ number of  year $=2$ is

$P=10,000$

$R=12\%p.a$

$n=2$

$A=P{(1+\frac{R}{100})}^n$

$=10,000{(1+\frac{12}{100})}^2$

$=10,000\times \frac{112}{100}\times \frac{112}{100}$

$=112\times 112=12544$

$C.I=A-P$

$=12544-10,000$

$=$ Rs.2544