The compound, ${Na}_{2} {IrCl}_{6}$ reacts with triphenylphosphine in diethylene glycol in an atmosphere of CO to give $[I r C l (C O) {(P P h_{3})}_{2}]$ $(Atomic number of Ir = 77)$ . Which of the following statements is/are correct?

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The IUPAC name of the complex is carbonylchloridobis (triphenyphosphine) Iridium (I) .

The complex shows geometrical as well as ionization isomerism .

The hybridization of the metal ion is ${sp}^{3} .$

The magnetic moment (spin only) of the complex is zero.

answer is A, C.

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Detailed Solution

$Hyb \to d s p^{2}, squareplanar. I r (5 d - s e r i e s)$ always form $squareplanar$ complexes

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