The compound P, Q and Swere separately subjected to nitration using HNO3/H2SO4 mixture. The major product formed in each case respectively is

Product is w.r.t to –OH as this reaction is electrophilic substitution and OH group is activating.Product is w.r.t – OCH3 as it is more ring activating than CH3Benzene ring to which O || -C- is attached becomes deficient in electrons due to – R nature of group. Rather to which –O– is attached becomes e¯ rich due to lone pair so product will be on that ring.

The compound P, Q and Swere separately subjected to nitration using HNO3/H2SO4 mixture. The major product formed in each case respectively is

Product is w.r.t to –OH as this reaction is electrophilic substitution and OH group is activating.Product is w.r.t – OCH3 as it is more ring activating than CH3Benzene ring to which O || -C- is attached becomes deficient in electrons due to – R nature of group. Rather to which –O– is attached becomes e¯ rich due to lone pair so product will be on that ring.

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The compound P, Q and S
were separately subjected to nitration using HNO₃/H₂SO₄ mixture. The major product formed in each case respectively is

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answer is C.

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Detailed Solution

Product is w.r.t to –OH as this reaction is electrophilic substitution and OH group is activating.

Product is w.r.t – OCH₃ as it is more ring activating than CH₃

Benzene ring to which $O | | - C -$ is attached becomes deficient in electrons due to – R nature of group. Rather to which –O– is attached becomes $\bar{e}$ rich due to lone pair so product will be on that ring.