The compound statement p→(~p ∨ q) is false, then the truth values of p and q are respectively

 p→(~p ∨ q) is false

If p is true, ~ p $\vee$ q is false.

 ~ p $\vee$ q is false. if $~\mathrm{p} \mathrm{is} \mathrm{false} \mathrm{and} \mathrm{q} \mathrm{is} \mathrm{false}$

 $\therefore$p is true(T); q is false(F)