Q.

The compound that will react most readily with NaOH to form methanol is

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a

CH33CCl

b

CH3OCH3

c

CH34N+I

d

CH32S+I

answer is A.

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Detailed Solution

Compound CH34N+I is most reactive due to (i) better leaving group, I- and (ii) due to the fact that the methyl group, with positive N, is not more electron deficient. Hence this group is more reactive towards nucleophile, OH-

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