The compound which does not exist, is

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${IF}_{7}$

${SF}_{6}$

${PbF}_{4}$

${IBr}_{7}$

answer is A.

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Detailed Solution

${IBr}_{7}$ does not exist.

${IBr}_{7}$ does not exist due to steric crowding). In order to acquire that level of stability and build a stable bond with iodine's noble gas structure, bromine has to be more electronegative.

Hence, option A is correct.

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