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The compound which is most reactive towards bromine gas is

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$C_{2} H_{4}$

$C_{2} H_{6}$

$C_{3} H_{6}$

$C_{4} H_{10}$

answer is C.

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Detailed Solution

${Br}_{2} (g)$ reacts through free radical mechanism but not by electrophilic mechanism;

$∴$ Free radical substitution occurs but not electrophilic addition;

The above list of free radicals are formed

It stabilizes through resonance .

Most reactive towards free radical bromination is ${CH}_{3} - CH = {CH}_{2}$

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