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Q.

The compound ${PCl}_{4} F$ in solid state exist as :

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a

${({PCl}_{4})}^{+} {({PCl}_{4} F_{2})}^{-}$

b

${({PCl}_{3} F)}^{+} {({PCl}_{5} F)}^{-}$

c

it does not exist as ions in the solid state

d

${({PCl}_{2} F_{2})}^{+} {({PCl}_{6})}^{-}$

answer is C.

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Detailed Solution

The compound ${PCl}_{4} F$ in solid state exist as ${({PCl}_{4})}^{+} {({PCl}_{4} F_{2})}^{-}$ because F prefers orbitals with less % s-character.

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