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The concentration of a solution containing 23g of phosphorous in 315g ${CS}_{2}$ is $2.34 mol {Kg}^{- 1} .$ The formula of phosphorous is (at mass of P = 31 ).

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$P_{6}$

$P_{4}$

$P_{2}$

answer is C.

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Detailed Solution

$m = \frac{n}{mass of solvent (g)} \times 1000 = 2.24$

$n = \frac{2.34 \times 315}{1000} = 0.737$

0.737 moles contain 23 gr

So, 1 mole contain = ?

$\frac{23}{0.737} = 31 g r = a t m o i c m a s s$

So, 1P atom.

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