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Q.

The concentration of oxalic acid is 'X' mol lit^-1 40 ml of this solution reacts with 16ml of 0.05 M acidified KMnO₄. What is the pH of 'X' M oxalic acid solution ? (Assume that oxalic acid dissociates completely)

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a

1.3

b

1.699

c

1

d

2

answer is C.

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Detailed Solution

Following redox reaction take place

5{H_2}{C_2}{O_4} + 2KMn{O_4} + 3{H_2}S{O_4}xrightarrow{{}}2MnS{O_4} + {K_2}S{O_4} + 10C{O_2} + 8{H_2}O

equivalents of H₂C₂O₄ = equivalents of KMnO₄

$\frac{40 \times M_{a} \times 2}{1000} = \frac{16 \times 0.05 M \times 5}{1000}; M_{a} = 0.05 M; N_{a} = 0.1 N; p^{H} = 1;$

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The concentration of oxalic acid is 'X' mol lit-1 40 ml of this solution reacts with 16ml of 0.05 M acidified KMnO4. What is the pH of 'X' M oxalic acid solution ? (Assume that oxalic acid dissociates completely)